(B) We can write $998$ as $(1000 - 2)$.Using the algebraic identity $(a - b)^{3} = a^{3} - b^{3} - 3ab(a - b)$,where $a = 1000$ and $b = 2$:$(998)^{3}

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(B) We can write $998$ as $(1000 - 2)$.Using the algebraic identity $(a - b)^{3} = a^{3} - b^{3} - 3ab(a - b)$,where $a = 1000$ and $b = 2$:$(998)^{3} = (1000 - 2)^{3}$$= (1000)^{3} - (2)^{3} - 3(1000)(2)(1000 - 2)$$= 1,000,000,000 - 8 - 6000(998)$$= 1,000,000,000 - 8 - 5,988,000$$= 994,011,992$